Understanding RLC Circuits: Calculating Current in a Series Circuit

Click For Summary
To analyze the series RLC circuit with the given parameters, start by applying Kirchhoff's Voltage Law (KVL) to establish a differential equation. The equation takes the form v'' + (R/L)v' + v/(LC) = E/(LC), where E is the electromotive force. Initial conditions, such as i(0) = 0 and q(0) = 0, help determine the initial values needed for solving the equation. Utilizing the Laplace transform is recommended for solving the second-order differential equation, especially due to the complexity introduced by the driving term E. This approach allows for easier manipulation and inversion of the results in the s domain.
kings13
Messages
27
Reaction score
0
A series RLC circuit has an electromotive force given by E=200e^(-100t) V, a resistor of 80 ohms, an inductor of 0.2 H, and capacitor of 5x10^-6 F. If the initial current and charge on the capacitor are zero, find the current at any time t>0.

How on Earth do i start this?!
 
Physics news on Phys.org
First, write a differential equation using KVL. Call the voltage across the cap, v(t). Then, the voltage across the inductor is Ldi/dt. The voltage across the resistor is iR. The driving voltage is E. Now, since i is going into a cap, we know that i=Cv', where v' is dv/dt. Then, putting it all together and dividng by LC gives v''+(R/L)v'+v/(LC)=E/(LC), where E is the EMF driving the circuit. Now, before you can solve this equation, you need to figure out your initial values. What does i(0)=0 imply about v'(0)? Use i(t)=Cv'(t) to find this initial value. Now, what does q(0)=0 imply about v(0)? Note that C=q(t)/V(t), so V(t)=q(t)/C.

Now you have a second order differential equation and you have two initial values to solve it. You can use any method you'd like to solve this equation, but you may find it difficult because of the driving term, E. I would suggest a Laplace transform. Then, if you get a weird answer in the s domain, use partial fractions to break it into parts which you can easily invert.
 

Similar threads

  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
981
Replies
44
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
12
Views
2K