Understanding Second-Order Reactions and the Rate Law Equation

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SUMMARY

A "second-order reaction" refers to the overall order of the reaction being 2, which can occur when two reactants each have an order of 1 or when one reactant has an order of 2 while another has an order of 0. The rate law equation for such a reaction can be expressed as r = k[x]^1[y]^1. In this case, the graph of the reaction rate will not be linear but rather a curve, indicating the relationship between the concentration of the reactants and the rate of reaction.

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  • Understanding of chemical kinetics
  • Familiarity with rate laws and reaction orders
  • Knowledge of graphing functions in chemistry
  • Basic algebra for interpreting rate equations
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  • Study the derivation of the rate law for second-order reactions
  • Learn how to graph concentration versus time for second-order reactions
  • Explore the implications of reaction order on reaction mechanisms
  • Investigate the differences between zero, first, and second-order reactions
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iBill
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So say if someone is referring to a "second-order reaction", are they referring to the overall order of reaction being 2? So two reactants could have an order of 1, or one reactant could have an order of 2, and the other have an order of 0?

So say you have a rate equation that looks like this: r = k[x]^1[y]^1

Would this graph be a linear line? or would it be a curve?



So pretty much what I'm asking is if someone says "second order reaction" are they referring to the overall order of reaction, or the order of reaction relative to one of the reactants.

Thx in advance.
 
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Without further clarification it usually means overall. Sometimes you may hear it said like "first order in X", then it is not overall, but relative to reactant X. So for example "reaction is first order in X and first order in Y, second order overall".
 

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