Understanding solution method for finding accelerations in a mechanical linkage

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The discussion revolves around the confusion between two equations for finding accelerations in a mechanical linkage. One participant initially used a formula that included a cross product term, leading to different results compared to Chegg's approach, which omitted this term. The key clarification is that the problem states the velocities are constant, implying zero angular acceleration. This explains why Chegg's solution neglects the cross product. The participant acknowledges the importance of carefully reading the problem statement to avoid misunderstandings.
whitejac
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Homework Statement


I was checking my work and Chegg uses the equations differently. Can somebody tell me why? Maybe I'm misunderstanding how/why to use the equation I chose.
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Steps 4-5.JPG

Homework Equations


They say aB = -ω2ABRB/Ai
I used aB = aA + αk x r - ω2rB/A

The Attempt at a Solution


So obviously mine will be a different answer, I only found aB but it gave me an i and j component because of that cross product. Which one is correct and why? Why can they neglect the cross product?
 
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The cross product term involves angular acceleration of the rod connecting A and B. In the Chegg problem, the angular acceleration is apparently zero.
 
How do they justify there being no angular acceleration? It doesn't say this is a static situation, so these bars should be rotating towards one another.
 
whitejac said:
How do they justify there being no angular acceleration? It doesn't say this is a static situation, so these bars should be rotating towards one another.

I figured it out. The problem states that the velocities are constant and therefore the angular accelerations are zero.
Man, reading is important. Thank you for explaining this to me!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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