Understanding the Basis of a Zero Vector Space

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The basis for a zero vector space is defined as the empty set, ∅, since it contains no vectors. The zero vector itself is not considered a basis because it is not linearly independent. In general, a vector space can have an infinite number of bases, except for the trivial case of the zero vector space. For polynomial vector spaces, the standard basis consists of {1, x, x², ..., xⁿ} for dimensions n or less. Understanding these principles is crucial for determining bases in various vector spaces.
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Homework Statement


erm, I just want to know, what is the basis for a zero vector space?


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The Attempt at a Solution


is it the zero vector itself? but if that's the case, then the constant alpha could be anything other than zero, which means the zero vector is not linearly independent...


another quick question, how do you determine the basis of a polynomial vector space in general?
 
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A basis is usually not defined for the trivial vector space, e.g. the basis is the empty set.
 
does that mean the basis for zero vector space is just ∅?

another quick question, how do you determine the basis of a polynomial vector space in general?
 
Unless I'm mistaken, yes. Although, some confirmation from the pro mathematicians here would be great.
 
Yes, the vector space consisting only of the 0 vector has the empty set as basis.

There is no such thing as "the" basis of any vector space. Except for the trivial case above, any vector space has an infinite number of possible bases. The "standard" basis for the vector space of polynomials of dimension n or less is {1, x, x2, ..., xn}. If you are talking about finding a basis for some subspace of such a space, how you would do that depends upon how the subspace is defined.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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