Understanding the Components of Non-Uniform Circular Motion

AI Thread Summary
In non-uniform circular motion, an object accelerating at a constant rate experiences both tangential and centripetal acceleration components. The tangential acceleration remains constant, while the centripetal acceleration increases as the object's speed increases. The total acceleration's magnitude also rises due to the interplay between these components. Changes in one component inherently affect the others, as they are interconnected through the object's circular motion. Understanding these relationships is crucial for accurately applying angular kinematic equations.
jasmaar
Messages
2
Reaction score
0
If an object is increasing speed at a constant rate around a circle, does the magnitude of acceleration still change since there are both the tangential acceleration component (whose magnitude is constant) and the centripetal component (which changes in magnitude as the object increases in speed)?
 
Physics news on Phys.org
The tangential and the centripetal component are at right angles.
The tangential component is constant.
The centripetal component increases.
Obviously the magnituded of the total acceleration also increases
 
If the object is accelerating at any rate then the magnitude of the angular, tangental, and centripetal components of the objects motion will also change. All the components of the ojects motion will change because they are all describing the same motion of the same object even if we as humans split its motion into many component motions on paper so we can fully describe in mathmatical terms. My point is that when an object is in circular motion you can not change one component of that motion without affecting the other components of its motion. Centripetal Acc. is based on Tangental speed and tangental speed is based on angular speed which is based on the measurement of angular displacement in a certain time interval which is simply motion in a circle. Take a close look at the angular kinematic equations and try to see how they all fir together. Please post the scenario that's giveing you troubles if this spiel doesn't help.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top