Understanding the derivation for Elastic Potential Energy.

Click For Summary
SUMMARY

The discussion focuses on the derivation of Elastic Potential Energy (EPE) using two methods: one based on Young's modulus and the other on Hooke's law. Both derivations yield the same result for work done, expressed as W = (AY/2L)x². The conversation also addresses the relationship between stress, strain, and volume in the context of EPE, clarifying that volume refers to AL, where A is the cross-sectional area and L is the length. Additionally, the importance of consistent sign conventions in derivations is emphasized, ensuring clarity in calculations related to stretching and compression.

PREREQUISITES
  • Understanding of Young's modulus (Y) and its application in material science.
  • Familiarity with Hooke's law and spring force (F = kx).
  • Basic knowledge of calculus, particularly integration techniques.
  • Concept of stress and strain in materials, including their mathematical definitions.
NEXT STEPS
  • Study the derivation of Elastic Potential Energy using Young's modulus in detail.
  • Explore the relationship between stress, strain, and volume in material mechanics.
  • Learn advanced integration techniques relevant to physics problems involving variable forces.
  • Investigate the conventions for sign usage in physics derivations and their implications.
USEFUL FOR

Students and professionals in physics, engineering, and material science who are interested in understanding the principles of Elastic Potential Energy and its derivations.

JC2000
Messages
186
Reaction score
16
Elastic Potential Energy of a Strained Body

(A) Using ## Y = \frac {stress}{strain}## we get ##F = \frac {AY}{L} * x## where ##F## is the restoring force, ##x## is the distance the body is stretched by.

Since Work = PE (spring force/ stress is conservative?)

Thus ##W = \int_{0}^{x} \frac {AY}{L} x dx ## which gives ##W = \frac {AY}{2L} x^2## (?)

OR

(B) For spring force we know ##F = kx## thus ## W = \frac {kx^2}{2}##
Comparing ##F=kx## to ##Y = \frac{FL}{Ax}## gives us ##k=\frac{FA}{L}## substituting this in the above result gives us ##W = \frac {AY}{2L} x^2##

My Questions :
1. Are both derivations correct?
2. My book also mentions ##U = 1/2 * Stress * Strain * Volume##, I am (a)not sure if volume refers to ##x^3## or ##L^3## and (b) I am unable to derive this result from ##W = \frac {AY}{2L} x^2## (apologies for the trivial question).

Slightly related :
3. I was solving a problem (A wire of mass ##m## and length ##l## is suspended from the ceiling. Due to its own weight it elongates, consider cross-section area ##A## and Young's modulus ##Y##. Find the elongation of the wire.) which also involves integration(?).

The solution :
Assume a small length of the wire ##dx## which elongates by ##\Delta dx## so that ##Y = \frac{T/A}{\Delta dx/dx}## which can be expressed as :
## \Delta dx = \frac {T}{YA}dx = \frac{mg}{YAl}*xdx##.

Thus, total elongation ##\Delta l = \int \Delta dx = \int_{0}^{l} \frac {mg}{YAl}*xdx = \frac{mgl}{2YA}##

Here I have two questions (c) Why is the fact that each small length of wire considered undergoes a slightly different F, ignored (I can't fathom how to deal with this though, some sort of 'double integration' possibly?)?

(d) How does ##\frac {T}{YA}dx = \frac{mg}{YAl}*xdx##

4. Lastly, throughout the derivation for stretching the body, signs are ignored, If I understand correctly. signs can be assigned as per convenience (for compression/ stretching or for work done by restoring force/ work done by system) and the chosen signs need to be mentioned initially for the sake of consistency (?). Is this rigorous enough? Or is there some convention that is generally followed here?

Thank you for your time!
 
Physics news on Phys.org
1. Yes
2. Volume = AL.
3. It's not ignored. T = mgx/L. If x is measured from 0 at the bottom to L at the top, the weight of the wire below the point x is mgx/L.
 
  • Like
Likes   Reactions: JC2000
Thank you very much that clears things up!
(4.?)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
936
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
12
Views
2K