Understanding the Impact of Bowling Ball Weight on Force: MV vs. 1/2MV^2

  • Context: Undergrad 
  • Thread starter Thread starter mtworkowski@o
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around the impact of bowling ball weight on the force exerted during a throw, specifically debating whether to use the momentum formula (MV) or the kinetic energy formula (1/2MV^2) in this context. Participants explore the relationship between mass, velocity, and energy delivery to bowling pins, touching on concepts from physics such as momentum, kinetic energy, and the conservation of energy and momentum.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants argue that neither MV nor 1/2MV^2 directly represents force, with one stating that force is defined as F=ma.
  • Others propose that when considering energy delivery to pins, mass (M) and velocity (V) are trade-offs, suggesting a heavier ball at a slower speed versus a lighter ball thrown faster.
  • One participant introduces the relativistic momentum formula, p = ɣmv, but others question its relevance given the speeds involved in bowling.
  • There is a suggestion that the energy delivered to the ball is constant regardless of mass if the same force is applied throughout the swing.
  • Some participants express confusion over whether to prioritize momentum or kinetic energy in their calculations, with one questioning the implications of using a squared velocity in the kinetic energy formula.
  • Another participant emphasizes the importance of accuracy in throwing, suggesting that a heavier ball may not always be preferable if it affects accuracy negatively.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether to use MV or 1/2MV^2 for their calculations, and there are multiple competing views regarding the relationship between mass, velocity, and energy delivery. The discussion remains unresolved with various interpretations and approaches presented.

Contextual Notes

Participants highlight the need for a well-defined problem to clarify the calculations being discussed. There are also mentions of assumptions regarding swing length and force application that may affect the conclusions drawn.

  • #31
mtworkowski@o said:
I don't think anyone can read. WHICH FORMULA DO I USE? I'M SICK OF ASKING. WHICH ONE A:MV B:1/2MV6^2 SAY A OR B. DON'T SAY ANYTHING ELSE. THANK YOU AND GOODBYE...
You don't "use" either formula. You're forcing us to answer an impossible question. If you want to know which is most closely related to the force the ball applies, it's 1/2mv^2. Don't get mad at us because you don't know how to ask a question right. You can't use either formula, it's dimensionally wrong. Instead divide 1/2mv^2 by d and you will get the force that it applies. End of story.
 
Last edited:
Physics news on Phys.org
  • #32
mtworkowski@o said:
I don't think anyone can read. WHICH FORMULA DO I USE? I'M SICK OF ASKING. WHICH ONE A:MV B:1/2MV6^2 SAY A OR B. DON'T SAY ANYTHING ELSE. THANK YOU AND GOODBYE...

Nice attitude. I think you need to spend more time trying to help people understand your poorly presented problem rather than throw a hissy fit and insult them.
Just use B, for what it's worth. Do you even know what to do with it to try to solve your "problem"?
Also, you might want to look a little harder at a physics textbook and get a basic understanding of things next time, or at least so you can get the terminology right (you know, before you go calling other people stupid).
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
24
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K
Replies
5
Views
1K