Understanding the Impact of Bowling Ball Weight on Force: MV vs. 1/2MV^2

  • Context: Undergrad 
  • Thread starter Thread starter mtworkowski@o
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SUMMARY

The discussion centers on the physics of bowling ball weight and its impact on force and energy delivery to pins. Participants clarify that neither MV (momentum) nor 1/2MV^2 (kinetic energy) directly represents force, which is defined as F=ma. The conversation emphasizes the trade-off between mass and velocity, noting that while a heavier ball may deliver more energy, accuracy and the ability to throw faster with a lighter ball are crucial factors. Ultimately, both momentum and energy conservation principles dictate the outcomes in bowling dynamics.

PREREQUISITES
  • Understanding of Newton's laws of motion, specifically F=ma.
  • Familiarity with the concepts of momentum (p = mv) and kinetic energy (KE = 1/2mv^2).
  • Basic knowledge of conservation laws in physics, particularly conservation of momentum and energy.
  • Awareness of the relationship between mass, velocity, and energy transfer in physical systems.
NEXT STEPS
  • Research the principles of conservation of momentum and energy in elastic collisions.
  • Explore the effects of mass and velocity on energy transfer in sports physics.
  • Study the dynamics of projectile motion and its applications in bowling.
  • Learn about the biomechanics of throwing techniques and their impact on performance.
USEFUL FOR

Physics students, bowling enthusiasts, coaches, and anyone interested in the mechanics of sports performance and energy transfer in physical activities.

  • #31
mtworkowski@o said:
I don't think anyone can read. WHICH FORMULA DO I USE? I'M SICK OF ASKING. WHICH ONE A:MV B:1/2MV6^2 SAY A OR B. DON'T SAY ANYTHING ELSE. THANK YOU AND GOODBYE...
You don't "use" either formula. You're forcing us to answer an impossible question. If you want to know which is most closely related to the force the ball applies, it's 1/2mv^2. Don't get mad at us because you don't know how to ask a question right. You can't use either formula, it's dimensionally wrong. Instead divide 1/2mv^2 by d and you will get the force that it applies. End of story.
 
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  • #32
mtworkowski@o said:
I don't think anyone can read. WHICH FORMULA DO I USE? I'M SICK OF ASKING. WHICH ONE A:MV B:1/2MV6^2 SAY A OR B. DON'T SAY ANYTHING ELSE. THANK YOU AND GOODBYE...

Nice attitude. I think you need to spend more time trying to help people understand your poorly presented problem rather than throw a hissy fit and insult them.
Just use B, for what it's worth. Do you even know what to do with it to try to solve your "problem"?
Also, you might want to look a little harder at a physics textbook and get a basic understanding of things next time, or at least so you can get the terminology right (you know, before you go calling other people stupid).
 

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