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Ok I know that the [tex]\int e^x = e^x + C[/tex]
now I don't understand this problem.
[tex]\int_0^1 e^{-3x} dx = -(1/3)e^{-3(0)} - -(1/3)e^{-3(1)}[/tex]
[tex]= 1/3(1- e^{-3} )[/tex]
Where does the 1/3 come from?
now I don't understand this problem.
[tex]\int_0^1 e^{-3x} dx = -(1/3)e^{-3(0)} - -(1/3)e^{-3(1)}[/tex]
[tex]= 1/3(1- e^{-3} )[/tex]
Where does the 1/3 come from?