Understanding the Oscillations of a Metronome

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The discussion focuses on the oscillations of a metronome, which can be modeled as simple harmonic motion. A metronome operates as a physical pendulum, where the torque acting on it when out of equilibrium restores it to equilibrium, leading to a differential equation similar to that of simple harmonic motion. The mechanical metronome features an adjustable weight on an inverted pendulum rod, allowing users to control the tempo by sliding the weight. This mechanism is often referred to as a double-weighted pendulum. Understanding these principles is essential for analyzing the metronome's oscillatory behavior.
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Homework Statement



Determine the equations governing the oscillations of a metronome.


The Attempt at a Solution



I believe that it has something to do with simple harmonic motion but I'm not sure where to start. Any help would be great.
 
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How does a metronome look like?ehild
 
The metronome is one similar to the one in the link below.

http://www.concertpitchpiano.com/Wittner_metronome_mahogany.jpg"
 
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Very good. Does not it look like a grandfather's clock but upside down? Yes, it performs oscillations, as a physical pendulum, and its motion can be considered as simple harmonic motion for small angles. The torque acting on the metronome when it is out of equilibrium tends to restore equilibrium and is equal to the angular acceleration times moment of inertia. For small angles, this leads to a differential equation identical with that for simple harmonic motion.

Here is a description of the mechanical pendulum from wikipedia:

"Mechanical metronomes

One common type of metronome is the mechanical metronome which uses an adjustable weight on the end of an inverted pendulum rod to control the tempo: The weight is slid up the pendulum rod to decrease tempo, or down to increase tempo. (The mechanism is also known as a double-weighted pendulum. There is a second, fixed weight on the other side of the pendulum pivot, hidden in the metronome case.) "
ehild
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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