1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Metronome question: Figuring out net torque and expression for beats per minute?

  1. Jan 20, 2012 #1
    1. The problem statement, all variables and given/known data

    A metronome is a device used by musicians to help them adjust
    the timing of their music to a standard number of beats per
    minute. The position of the moveable slider determines the
    frequency. It is possible to build a simple mechanical
    metronome using a light stick and two masses, as shown in the
    diagram.

    (a) Assume the metronome is displaced from the vertical by an
    angle, theta, as shown in the figure. Find an expression for the net
    torque on the metronome about the pivot. Go through the
    necessary steps to show that it will oscillate in SHM providing 
    is a small angle and M1L1 > M2L2. Find an expression for the
    number of beats per second of the metronome (note that there
    are 2 beats per cycle of oscillation).

    (b) Suppose M1 = 0.200 kg, M2 = 0.0500 kg, and L1 = 5.0 cm. Calculate the number of
    beats per minute if:
    (i) L2 = 16.3 cm. (Check your answer: 60 beats per minute.)
    (ii) L2 = 6.8 cm.

    Here is the image for the problem question I am having: http://i43.tinypic.com/sgiwb5.png



    2. Relevant equations



    3. The attempt at a solution

    Really need help with this:

    The torque on M1 is –(M1 *g * L1 *sin(theta)) correct???? The torque on M2 is positive (CCW). I add them together to get net torque right?

    How do I add them together?

    Also after that, how do I find an expression for the numbe of beats per second, as stated in the question.
     
  2. jcsd
  3. Jan 20, 2012 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Here is the image for anybody reading this thread.

    attachment.php?attachmentid=42882&stc=1&d=1327090160.png
     

    Attached Files:

  4. Jan 20, 2012 #3
    Thanks sammy!

    Any help on this would be great! Having some issues :(
     
  5. Jan 21, 2012 #4
    Anyone? :)
     
  6. Jan 21, 2012 #5
    is this correct?

    The mechanism is a physical pendulum. f = (1/2π)√[m*g*L/I] where m = M1+M2, L = distance from CM to pivot, and I = moment of inertia about pivot.
    Ergo, beat frequency fb = f/2 = (1/4π)√[mgL/I]
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Metronome question: Figuring out net torque and expression for beats per minute?
  1. Revolutions per minute (Replies: 1)

Loading...