Understanding the Potential Energy of a Dipole in an Electric Field

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The discussion centers on the relationship between torque exerted on a dipole in an electric field and the work done during its rotation. The torque is defined as τ = p × E, and the work done to rotate the dipole from angle θ1 to θ2 is expressed through the integral of torque. There is confusion regarding whether this integral represents the work done by the electric field, as potential energy is defined as the negative of the work done by conservative forces. Clarification is provided that the angle θ in the potential energy formula is measured from the electric field direction to the dipole moment, indicating that the torque considered is indeed the opposite of the torque related to the dipole's rotation. Understanding this relationship is crucial for grasping the concept of potential energy in the context of dipoles in electric fields.
DavideGenoa
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Hi, friends! I read that the torque exerced by a uniform electric field ##\mathbf{E}## on a dipole with moment ##\mathbf{p}## is ##\boldsymbol{\tau}=\mathbf{p}\times\mathbf{E}##. Then the book, Gettys' Physics 2, explain that the work made to rotate the dipole around a fixed point is

##\int_{\theta_1}^{\theta_2}\tau d\theta=\int_{\theta_1}^{\theta_2}pE\sin\theta d\theta=-pE\cos\theta_2-(-pE\cos\theta_1)=\Delta U##
and therefore potential energy can be defined as ##U=-\mathbf{p}\cdot\mathbf{E}##.

Well, there is a major obstacle to my comprehension of that: I think that ##\int_{\theta_1}^{\theta_2}\tau d\theta=\int_{\theta_1}^{\theta_2}pE\sin\theta d\theta## (where I think ##\theta## to be the oriented angle from ##\mathbf{p}## to ##\mathbf{E}##) is the work done by the electric fied while the dipole rotates from an angle ##\theta_1## with the direction of ##\mathbf{E}## to an angle ##\theta_2## with ##\mathbf{E}##, but I know the definition of the variation of potential energy ##\Delta U## as the opposite of the work done by a conservative force field: ##\Delta U=-W_{\text{conservative}}##.

Or isn't ##\int_{\theta_1}^{\theta_2}\tau d\theta## the work done by the electric field? I would think that it is, because the work done by a force ##\mathbf{F}## to move along the circumference ##\gamma## parametrized by ##\mathbf{r}:[0,2\pi]\to\mathbb{R}^3## is ## \int_{\theta_1}^{\theta_2} \mathbf{F}(\mathbf{r}(t))\cdot \mathbf{r}'(\theta)d\theta##. Here ##\mathbf{F}\cdot \mathbf{r}'=F_t R## where ##F_t## is the tangential component of the force (positive if and only if counterclockwisely oriented) and ##R## the distance of the moved object from the centre of the circle and, if I correctly understand, ##RF_t## precisely is the torque ##\tau_z## with respect to the centre of rotation of a rotating body, therefore the work done by the forces acting on the rotating body are ##W_{\text{tot}}=\int_{\theta_1}^{\theta_2} \sum\tau_z d\theta##. Or am I wrong?

I heatily thank you for any answer!​
 
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I have understood: in the formula for ##\Delta U## the angle ##\theta## is from ##\mathbf{E}## to ##\mathbf{p}##, i.e ##\tau## is the opposite of the torque ##\tau_z##.
 
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