Understanding the Relationship between Absolute Value and Complex Numbers

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The discussion centers on the relationship between the absolute value (modulus) of a complex number and its algebraic properties. It clarifies that for a complex number z = a + ib, the expression |z|^2 equals z*z, which simplifies to a^2 + b^2. However, it emphasizes that |z|, defined as sqrt(a^2 + b^2), is not the same as z^2, which expands to a^2 + 2iab - b^2. The distinction is made that while the modulus can be seen as a form of absolute value for real numbers, it does not equate to the square of the complex number itself. Understanding these differences is crucial for grasping complex number properties in mathematics.
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Why is |z|^2 = z*z?

z = a + ib
z*z = (a - ib)(a + ib) = a^2 + b^2
z^2 = (a + ib)^2 = a^2 + 2iab - b^2

So it must have something to do with the absolute value, but I don't understand what or why.
 
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|z| does not define the "Absolute Value" of a complex number. The notation |z| refers to the modulus of z, which is by definition

|z| = sqrt(a^2 + b^2)

Geometrically it gives the distance of the complex number from the origin on the Argand Plane.

And quite obviously |z|^2 is NOT EQUAL TO z^2
 
|z|^2 is conjugate(z)*z=a^2+b^2. It's not equal to z^2.
 
although the modulus of z when z is of the form a + 0i (i.e. it is only in the reals), then wouldn't that be essentially like an absolute value?
 
Sure. Modulus of z is |z| is sqrt(a^2+b^2). It's still not the same as z^2. What's the question again?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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