Understanding the Thin Lens Equation: How to Graph and Interpret Results

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Homework Help Overview

The discussion revolves around the thin lens equation and its application in graphing and interpreting results. Participants are exploring the relationships between object distance (do), image distance (di), and focal length (f).

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify the correct form of the thin lens equation and its implications for graphing. There are questions about the validity of the equation provided by the original poster and concerns regarding unit consistency.

Discussion Status

The discussion is ongoing, with participants questioning the accuracy of the equation and exploring the implications of graphing it. Some guidance has been offered regarding the need for correct variable values to proceed with graphing.

Contextual Notes

There is uncertainty about the correct formulation of the thin lens equation, and participants are discussing the potential need for a 3D graph if certain variable values are unknown.

Larrytsai
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I need to learn how to graph do=1/(f -1/di) like i have my measurements and when i plug in my di i get a do so what do i do with my old do?
 
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Larrytsai said:
do=1/(f -1/di)

Are you sure that's the correct equation? Shouldn't it be the following?

[tex]d_o=\frac{fd_i}{d_i-f}[/tex]
 
Tom Mattson said:
Are you sure that's the correct equation? Shouldn't it be the following?

[tex]d_o=\frac{fd_i}{d_i-f}[/tex]

umm that's the way my teacher wrote it. Iduno he might be wrong lol
 
I don't think you typed it in correctly. In the denominator you have f-1/di. You're subtracting a distance and an inverse distance. The units don't work out. Please check it. Also, when you say you need to graph the equation, do you know the values of any of the variables do, di, or f? If not, then you'll have to do a 3D graph, which is much more involved.
 

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