Understanding the Time Average and Its Meaning in Physics

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SUMMARY

The discussion focuses on the concept of time average in physics, specifically addressing the formula for calculating it. The correct interpretation of the time average is given by the equation $$\frac{\int_0^T{u'(t)v'(t)dt}}{T}$$, which represents the average of the product of two functions over a specified time interval T. This clarification corrects the initial misunderstanding that equated the time average to a simple division of squared units.

PREREQUISITES
  • Understanding of calculus, specifically integration.
  • Familiarity with the concepts of time averages in physics.
  • Knowledge of physical quantities and their units, such as velocity (ms^-1).
  • Basic understanding of functions and their representations in physics.
NEXT STEPS
  • Research the application of time averages in different physical contexts.
  • Study integration techniques for calculating averages over time.
  • Explore the significance of the product of functions in physics.
  • Learn about other averaging methods used in physics, such as root mean square.
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Students studying physics, educators teaching concepts of averages in motion, and anyone interested in the mathematical foundations of physical principles.

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Homework Statement


what is the meaning of the circled time average there? does it mean ( (ms^-1)(ms^-1) ) /2 ?

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The Attempt at a Solution


does it mean ( (ms^-1)(ms^-1) ) /2 ?
 

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No. It means

$$\frac{\int_0^T{u'(t)v'(t)dt}}{T}$$
 
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