Understanding the Units in Relativistic Momentum Calculations

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Discussion Overview

The discussion revolves around the calculation of relativistic momentum for an electron moving at 0.600c, specifically focusing on the units involved in the calculations and the conversion to MeV/c. Participants explore different methods of calculating momentum and the implications of unit conversions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the momentum using the mass of the electron in kg and expresses concern about the unit conversion to MeV/c, questioning why both methods yield the same numerical result.
  • Another participant provides a detailed conversion of MeV to kg*m/s and calculates the expected momentum, noting a discrepancy with the initial calculations and suggesting that the momentum should be 0.384 MeV/c.
  • A third participant confirms their calculation of 0.383 MeV/c, expressing initial confusion about the unit consistency in their calculations.
  • A later reply questions the original method of dividing by 1,000,000 and multiplying by c, indicating that the resulting value does not align with the expected momentum in MeV/c.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of the calculations and the methods used. There is no consensus on the resolution of the unit conversion issue, as some participants have arrived at slightly different numerical results.

Contextual Notes

Participants rely on specific constants and unit conversions, which may introduce assumptions about the accuracy of these values. The discussion does not resolve the discrepancies in the calculated momentum values.

jk4
I was working a problem in a Modern Physics book:
Find the momentum (in MeV/c) of an electron whose speed is 0.600c.

My first approach was:
mass of electron = 9.1E-31 kg

[tex]\sqrt{1 - \frac{(0.600c)^{2}}{c^{2}}} = 0.800[/tex]

[tex]p = \frac{9.1E-31 * 0.600c}{0.800} = 2.04E-22[/tex] (ignoring units)

then I needed to convert to MeV/c so with some messing around I ended up dividing by 1,000,000 and then multiplying by c to get the exact answer in the book. But this bothered me because I thought I had MeV then multiplying by c to get the answer in the book in MeV/c which doesn't make sense...

I then realized if I first convert the mass into [tex]\frac{MeV}{c^{2}}[/tex] then the units work out perfectly. But I'm still curious why I get the same answer doing it the first way, could someone please help me understand why it works out?
 
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jk4 said:
I was working a problem in a Modern Physics book:
Find the momentum (in MeV/c) of an electron whose speed is 0.600c.

My first approach was:
mass of electron = 9.1E-31 kg

[tex]\sqrt{1 - \frac{(0.600c)^{2}}{c^{2}}} = 0.800[/tex]

[tex]p = \frac{9.1E-31 * 0.600c}{0.800} = 2.04E-22[/tex] (ignoring units)

then I needed to convert to MeV/c so with some messing around I ended up dividing by 1,000,000 and then multiplying by c to get the exact answer in the book. But this bothered me because I thought I had MeV then multiplying by c to get the answer in the book in MeV/c which doesn't make sense...

I then realized if I first convert the mass into [tex]\frac{MeV}{c^{2}}[/tex] then the units work out perfectly. But I'm still curious why I get the same answer doing it the first way, could someone please help me understand why it works out?
According to this, 1 MeV = 1.60217653 * 10^-13 J (and 1 J = 1 kg * m^2 / s^2). So, 1 MeV/c = (1.60217653 * 10^-13 / 299792458) kg * m / s = 5.34428565 * 10^-22 kg * m / s. And if the mass of an electron is 9.11 * 10^-31 kg, then its momentum at 0.6c is (9.11 * 10^-31 * 0.6 * 299792458 / 0.8) kg * m / s = 2.05 * 10^-22 kg * m / s. This is 0.384 the size of 5.34428565 * 10^-22 kg * m / s which I found above for the value of 1 MeV/c, so the momentum of the electron at 0.6c should be 0.384 MeV/c...is this different from what you got?
 
Last edited:
I got 0.383MeV/c so you that's what I got. I was just confused about how the units worked themselves out in my first method of computing the answer, but thanks to your post I see it.
 
jk4 said:
I got 0.383MeV/c so you that's what I got. I was just confused about how the units worked themselves out in my first method of computing the answer, but thanks to your post I see it.
So is your question from the original post resolved? I was confused about what you meant when you said you divided by 1,000,000 and multiplied by c to get the correct answer, since 2.04*10^-22 * 299792458 / 1,000,000 = 6.12 * 10^-20, which isn't even close to 0.384.
 

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