Understanding the use of a figure in thermodynamics.

[Mbywater94]

I came across an equation used in one of the forums from a few years ago.

Found here: https://www.physicsforums.com/threads/calculate-how-long-it-will-take-for-the-ice-to-melt.531908/

I am researching a similar topic into melting ice and using it as a cooling solution.

However when i came across this equation everything was done correctly but a figure stuck out.

Why is the value of water's "Lf = 3.35 × 10⁵ J kg^-1" when in all other areas of the internet it is valued at 334 j / g?

I want to use this method to solve my own issue with a container but which value is correct for this equation?

Any assistance is greatly appreciated.

Thanks
Michael

 

[Ken G]

Converting from "per kg" to "per g" means dividing by 1000. If you divide 3.35 times 10⁵ by 1000, you get 335. Are you asking about the difference between 335 and 334? Sounds like a simple rounding difference.

 

[Mbywater94]

Converting from "per kg" to "per g" means dividing by 1000. If you divide 3.35 times 10⁵ by 1000, you get 335. Are you asking about the difference between 335 and 334? Sounds like a simple rounding difference.

I see my error, yes it is a simple rounding difference. It just threw me off a first glance, its been a long night hehe! Problem solved!