Understanding Velocity in Waves

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The discussion revolves around calculating the mass per unit length of a guitar string vibrating at 110 Hz with a length of 0.648 m and tension of 100 N. The user initially questioned why the wave velocity calculated from the string's tension and mass per unit length is significantly lower than the speed of sound in air (approximately 343 m/s). It was clarified that the velocity in this context refers specifically to the wave speed along the vibrating string, which is influenced by the string's tension and mass per unit length. The user ultimately expresses understanding of the concept after the clarification. The conversation highlights the distinction between wave velocity in different media.
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Homework Statement


I was told that a string on a guitar vibrates at a frequency of 110 Hz. The length of the string is .648 m and the tension is 100 N. I was told to find the mass per unit length, μ, of the string. Although I got the correct answer, I was wondering why my initial attempt was incorrect (shown below).

Homework Equations


f_{n} = \frac{n}{2L}v

v = \sqrt{\frac{T}{μ}}

The Attempt at a Solution


dakdX.jpg


(Sorry for the formatting, I don't type in latex really quickly).

In this case, if it's a guitar, why is the velocity of the wave not equivalent to 345 m/s (343.2 m/s)? Why is it so much lower (142.56 m/s)?

Thank you.
 
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Oh, is the velocity referring to the velocity of the vibrating string?

I think I understand now.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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