Understanding Wave Impedence: When \eta < \eta_0

  • Thread starter Thread starter Swapnil
  • Start date Start date
  • Tags Tags
    Wave
AI Thread Summary
When an electromagnetic wave transitions from free space to a lossless medium with a refractive index greater than one, its wave impedance decreases due to the relationship between impedance, speed of light, and refractive index. The wave impedance in free space is defined as η₀, while in a medium, it is modified by the refractive index n, resulting in η = η₀/n. This reduction in impedance can be intuitively understood as the wave encountering a medium that slows it down, leading to a higher density of energy in the medium compared to free space. Consequently, the wave's ability to propagate is altered, resulting in a smaller impedance value. Understanding this concept is crucial for analyzing wave behavior in different media.
Swapnil
Messages
459
Reaction score
6
When a em-wave goes from free space to a lossless medium with a n &gt; 1, why is it that the wave impedence \eta becomes smaller i.e. \eta = \frac{\eta_0} { n}. I know why from the math but I how to get to this result just by some intuitive reasoning?
 
Physics news on Phys.org
Anyone?
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top