1. The problem statement, all variables and given/known data y''-4y=60e4t y(0)=9 and y'(0)=2 2. Relevant equations none in particular 3. The attempt at a solution First I solved for the auxiliary equation. r2-4r r(r-4) r=0, 4 So the general solution for the homogenous form is C1e0x+C2e4x where C1 and C2 are unknown coefficients to be found. The particular solution is calculating by considering Yp= AXe4x Differentiating that twice, and solving for Yp, I get Yp=15xe4x So the general solution for this is obtained by adding the homogeneous and the particular. So I get: C1e0x+C2e4x +15xe4x I differentiated this equation and got 4C2+15e4x+60x4x So then I got 4C2+15=2, so C2=-3.25 Also, from the general solution C1+C2=9, so C1=12.25 The final answer I got was (12.25)e0x+-3.25e4x+15xe4x but this is wrong. Any ideas?