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Uniform angular acceleration - degrees per second?

  1. Oct 1, 2007 #1
    1. The problem statement, all variables and given/known data

    A wheel is subjected to uniform angular acceleration. Initially its angular velocity is zero. During the first 1-s time interval, it rotates through an angle of 88.6degrees.

    (a) Through what angle does it rotate during the next 1-s time interval?
    (b) Through what angle during the third 1-s time interval?

    2. Relevant equations

    a = (wf - wi)/(tf-ti)
    360 degrees = 2*pi*radians

    3. The attempt at a solution

    i found a = 1.546, where do i go from here?
  2. jcsd
  3. Oct 1, 2007 #2


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  4. Oct 1, 2007 #3
    okay, i came up with 132.87 degrees using one of the equations, do i subtract 88.6 degrees (the original rotation?)
  5. Oct 1, 2007 #4
    i am so confused, and everything i try is wrong
  6. Oct 2, 2007 #5


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    Yes, assuming you have calculated the angle turned in 2 secs. It's not very helpful to say "using one of the equations". But I think you are wrong because I'd expect more turn in the second period than the first ( because the speed is increasing linearly).
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