Uniform Circular Motion and Water Falling From A Bucket

AI Thread Summary
A 2kg bucket of water swung in a vertical circle at 12 m/s requires a minimum speed to retain the water, determined by the tension forces at the top and bottom of the swing. At the bottom, the maximum tension is 212 N, while at the top, the minimum tension is 172 N, factoring in gravitational force. The centripetal force is calculated using the formula (mv²)/r, where m is the mass and r is the radius. Understanding the forces acting on the water is crucial, as the bucket can only exert a pushing force, not a pulling one. The discussion emphasizes the importance of maintaining sufficient speed to prevent the water from spilling out.
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1. A 2kg bucket of water is attached to a 1.5m long string and swung in a vertical circle with a constant speed of 12 m/s. What is the minimum speed the bucket can be swung at while still retaining the water.


2. The bucket has a maximum tension force on the string at the bottom, with 212 N (198 N + the force of gravity). At the top, it has a minimum tension force, with 172 N (198 - gravity). The centripetal force can be found using (mv2)/(r), where v is the velocity, m the mass of the rotating object, and r the radius.


3. I'm honestly lost here. I know there has to be some sort of minimum speed, because conceptually I can see that with a huge radius and a low speed the water will fall out regardless of centripetal force. That's about it. -___-
 
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Think in the way that the water in the bucket travels along a circle of given radius. What forces act on it? The resultant of these forces must be equal to the centripetal force. From this condition, you get the normal force. Note that the bucket can only push the water, it can not pull it. ehild
 
Just think that what will cause the water to spill out of the bucket. Then try to minimize it.
 
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