Uniform Ciruclar Motion (whirling cord)

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Homework Help Overview

The discussion revolves around a problem involving uniform circular motion, specifically analyzing the motion of a 200g object tied to a cord and whirled in a circle on a frictionless table. Participants are tasked with determining the object's velocity, acceleration, and the tension in the cord.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculations for velocity and acceleration, with one participant expressing confusion regarding the tension calculation. There is a mention of unit conversion and the importance of distinguishing between vertical and horizontal forces.

Discussion Status

Some participants have provided guidance on unit conversions and the correct application of forces in the context of horizontal motion. There is acknowledgment of errors in the initial calculations, but no consensus has been reached on the complete resolution of the problem.

Contextual Notes

Participants note the need to convert grams to kilograms for accurate calculations and discuss the implications of horizontal versus vertical forces in the context of the problem.

KatieLynn
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Homework Statement



A 200g object is tied to the end of a cord whirled around on top of a horizontal and frictionless table top in a 2.4 diameter circle at 3 rev/s. Determine a) the velocity of the object b)t he acceleration of the object and c)t he tension in the cord.

Homework Equations



Vc = (2*pi*r)/T

Ac = (Vc^2)/R

Fnet = MA

Ft - Fg =MAc

The Attempt at a Solution



So for A) I got Vc = (2*pi*1.2)(1/3) which equals 22.3 m/s

Then for B) I got Ac=(22.6)^2/(1.2) which equals 425.6 m/s

Now here's where I get lost

I tried doing this but it doesn't come out right...

Fnet = MA

Ft - Fg =MAc

Ft - 196.2 = (20)(425.6)

which means Ft = 8708.2N, I know the answer should be Force of tension = 85.1N, I'm not sure what I'm doing wrong.
 
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200g=.2kg. Change to kg if you want the answer in Newtons. Watch your units.
 
KatieLynn said:

Homework Statement



A 200g object is tied to the end of a cord whirled around on top of a horizontal and frictionless table top in a 2.4 diameter circle at 3 rev/s. Determine a) the velocity of the object b)t he acceleration of the object and c)t he tension in the cord.

Homework Equations



Vc = (2*pi*r)/T

Ac = (Vc^2)/R

Fnet = MA

Ft - Fg =MAc

The Attempt at a Solution



So for A) I got Vc = (2*pi*1.2)(1/3) which equals 22.3 m/s

Then for B) I got Ac=(22.6)^2/(1.2) which equals 425.6 m/s

Now here's where I get lost

I tried doing this but it doesn't come out right...

Fnet = MA

Ft - Fg =MAc

Ft - 196.2 = (20)(425.6)

which means Ft = 8708.2N, I know the answer should be Force of tension = 85.1N, I'm not sure what I'm doing wrong.
you did fine in a and b. In c, however, you included the weight, but since the object is being twirled on a horizontal tabletop, the centripetal force and acceleration acts horizontally. The weight acts vertically.
 
PhanthomJay said:
you did fine in a and b. In c, however, you included the weight, but since the object is being twirled on a horizontal tabletop, the centripetal force and acceleration acts horizontally. The weight acts vertically.

Yes, there's that too. I missed it.
 
Ahh that you so much. I, for some reason, was converting 200g to 20kg, now that I switched it to .2kg and took out the force normal I got the right answer. Thank youuu :)
 

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