Uniform Continuity: Showing f*g Is Uniformly Continuous on Bounded X

Click For Summary

Homework Help Overview

The problem involves demonstrating that the product of two uniformly continuous and bounded functions, f and g, is also uniformly continuous. The context is rooted in the properties of uniform continuity and boundedness within a specified domain X.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of boundedness on uniform continuity and express uncertainty about how to proceed with the proof. There is a mention of the need to show that the product of the functions remains uniformly continuous under the given conditions.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some have raised questions about the necessity of both functions being bounded and how that relates to uniform continuity. A hint has been provided regarding the use of epsilon-delta arguments to approach the proof.

Contextual Notes

There is a focus on the definitions of uniform continuity and boundedness, with participants questioning the assumptions and implications of these properties in the context of the problem.

CarmineCortez
Messages
30
Reaction score
0

Homework Statement


suppose f and g are uniformly continuous functions on X

and f and g are bounded on X, show f*g is uniformly continuous.


The Attempt at a Solution



I know that if they are not bounded then they may not be uniformly continuous. ie x^2
and also if only one is bounded they are not necessarily uniformly continuous.

not sure what to do if they are both bounded
 
Physics news on Phys.org
CarmineCortez said:

Homework Statement


suppose f and g are uniformly continuous functions on X

and f and g are bounded on X, show f*g is uniformly continuous.


The Attempt at a Solution



I know that if they are not bounded then they may not be uniformly continuous. ie x^2
and also if only one is bounded they are not necessarily uniformly continuous.
No, you don't "know" that. In fact, here, you are told that they are both uniformly continuous.

not sure what to do if they are both bounded
Are you saying you could do this if only one were bounded? Do you understand what it is you are asked to prove?
 
uniform continuity is intuitively a bit like saying the function doesn't have an infinite slope anywhere...
And if they are both bounded, is their product too bounded?
 
Get your epsilons and deltas out. You want to show |f(x)g(x)-f(y)g(y)| can be made uniformly small if |x-y| is small. Hint: |f(x)g(x)-f(y)g(y)|=|f(x)g(x)-f(x)g(y)+f(x)g(y)-f(y)g(y)|. |f(x)-f(y)| and |g(x)-g(y)| can be made small since they are uniformly continuous. Do you see why f and g need to be bounded? Use epsilons and deltas to make the meaning of 'small' precise.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
26
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 13 ·
Replies
13
Views
13K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K