(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Let X be a discrete random variable with the p.m.f given in the following table:

x 10 20 30 40

p(x) .25 .2 .4 .15

Suppose you can generate a random value, u, from a uniform(0,1) distribution.

If u = 0.576, then what is the value of your random value from the distribution of X?

2. Relevant equations

F(x) = [tex]\int f(x)[/tex]dx

Uniform:

f(x) = (a+b)/2

3. The attempt at a solution

I've attempted to find the C.D.F of the table:

x 10 20 30 40

p(x) .25 .45 .85 1

From here I am at a complete loss at how to use my value of U to get at a random value of X. I did attempt the following but am unsure of its validity:

u = [tex]\int[/tex](1/30)dx from 10 to x, finding approximately 27 as the value. This seems very wrong to me as that makes me assume that the table is a uniform distribution which it is not.

I could truly use some help. Thanks a lot.

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# Homework Help: Uniform Distribution (Probability)

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