Unit Conversion (Fluid Mechanics)

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To calculate the density in lbm/ft3 using the formula ρ=p/RT with p=35 psi, R=1716 ft-lbf/slug-°R, and T=100°F, the initial conversion of temperature to Kelvin is noted. The user attempts to convert pressure from psi to lb/ft2 and applies various unit conversions, but is left with an incorrect unit of lb-s2/ft4. To achieve the desired density in lbm/ft3, it is suggested to multiply the result by the acceleration due to gravity, g, which is 32.2 ft/sec². Further calculations are needed to finalize the density conversion.
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Homework Statement


Calculate the density in lbm/ft3 with the given formula: ρ=p/RT where p=35 psi, R=1716 ft-lbf/slug-°R, and T=100°F.

We have access to a table with basically any unit conversion we would need.

The Attempt at a Solution


100°F=37.78°C=310.9278K

(35 lb/in2)(144 in2/1 ft2)(1 slug-°R/1716 ft-lbf)(32.17 lbm/1 slug)(1.8K/1°R)(1 lbf/32.17 lbm-ft/s22)(1/310.9278K)

I didn't crunch the numbers yet, because I know I haven't finished. Right now, this gives me an answer in lb-s2/ft4

Any help in getting this into lbm/ft3 would be greatly appreciated.
Thank you.
 
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Multiply by g which is 32.2 ft/sec^2.
 

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