B Units for Entropy of Simple Black Holes

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Gerard 't Hooft's equation for the entropy of a simple black hole is S = A/(4hG), where S is entropy, A is the area of the event horizon, h is reduced Planck's constant, and G is the gravitational constant. The initial interpretation of the units for entropy as seconds cubed per meters cubed was found to be incorrect due to missing constants. It was clarified that a factor of k_B c^3 is needed, with k_B representing the Boltzmann constant, which has units of energy per temperature. This adjustment resolves the unit discrepancy and aligns with the conventional representation of entropy in joules per kelvin. The discussion highlights the importance of including all relevant constants in physical equations.
muzukashi suginaiyo
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Hello. I recently discovered Gerard 't Hooft's (what a complicated name to type, isn't it?*apostrophe*apostrophe*apostrophe) equation for the entropy of a simple black hole (what is meant by "simple" I have no idea). It is:

Where "S" is the entropy of a simple black hole
A is the area of the black hole's event horizon
h is (reduced?) Planck's Constant
G is the gravitational constant

S = A/(4hG)

Unless there is a conversion constant missing in this equation (is there?), I get units for entropy as (s^3)/(m^3).

That is,

Entropy = [m^2]/[(kg*m^2/s)*(m^3/kg*s^2)]

= seconds cubed per meters cubed? What does this signify? Is there some "speed" associated with entropy such that entropy is inversely proportional to the cube of this "speed"?

Or am I way off track here?
 
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I've never heard of entropy referred to in ##\frac {s^3} {m^3}##. Generally it's given as ##\frac J K##.
 
muzukashi suginaiyo said:
Hello. I recently discovered Gerard 't Hooft's (what a complicated name to type, isn't it?*apostrophe*apostrophe*apostrophe) equation for the entropy of a simple black hole (what is meant by "simple" I have no idea). It is:

Where "S" is the entropy of a simple black hole
A is the area of the black hole's event horizon
h is (reduced?) Planck's Constant
G is the gravitational constant

S = A/(4hG)

Unless there is a conversion constant missing in this equation (is there?), I get units for entropy as (s^3)/(m^3).

That is,

Entropy = [m^2]/[(kg*m^2/s)*(m^3/kg*s^2)]

= seconds cubed per meters cubed? What does this signify? Is there some "speed" associated with entropy such that entropy is inversely proportional to the cube of this "speed"?

Or am I way off track here?
You're missing a factor of ##k_B c^3##. The three factors of ##c## cancel out the ##s^3/m^3##, while the Boltzmann constant ##k_B## has units of energy per unit temperature (typically J/K, as TJGilb mentioned). You can see this at the Wikipedia page here:
https://en.wikipedia.org/wiki/Black_hole_thermodynamics
 
Ah. Okay. So there was a couple constants missing. Thanks.
 
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