Units in Rings: show 1-ab a unit <=> 1-ba a unit

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SUMMARY

The discussion centers on proving that in a ring R with a multiplicative identity, the element 1-ab is a unit if and only if 1-ba is a unit. The proof begins by assuming that 1-ab is a unit, leading to the existence of a unit u in R such that (1-ab)u = 1. The key insight involves manipulating the equation to relate 1-ab and 1-ba, specifically using the identity (1-ab)a = a(1-ba) to establish the equivalence of the two units.

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Students and educators in abstract algebra, particularly those focusing on ring theory, as well as mathematicians interested in the properties of units within algebraic structures.

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Homework Statement


Let R be a ring with multiplicative identity. Let a, b \in R.
To show: 1-ab is a unit iff 1-ba is a unit.

The Attempt at a Solution


Assume 1-ab is a unit. Then \exists u\in R a unit such that (1-ab)u=u(1-ab)=1

\Leftrightarrow u-abu=u-uab \Leftrightarrow abu=uab. Not sure if this is useful, I haven't been able to go anywhere with it...

I also tried (1-ab)(1-ba)=1-ab-ba+abba but this isn't giving me any inspiration either.

Ideas on how to solve this?
 
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Ok, so u(1-ab)=1. You want to get ba into the picture somehow. So multiply on the left by b and on the right by a. So bu(1-ab)a=ba. Now the big hint is that (1-ab)a=a(1-ba).
 

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