Unraveling the Structure of XeF6: VSEPR and Valence Bond Theories

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SUMMARY

The structure of Xenon hexafluoride (XeF6) is confirmed to be a pentagonal bipyramid, as established through VSEPR and Valence Bond theories. XeF6 exhibits sp3d3 hybridization, which accounts for its geometry. The confusion regarding iodine hexafluoride (IF6) is clarified, as the stable species is [IF6]+, which possesses an octahedral structure. The presence of a lone pair in XeF6 differentiates its structure from that of IF7, which lacks a lone pair and thus has a different geometry.

PREREQUISITES
  • Understanding of VSEPR theory and its application to molecular geometry
  • Familiarity with Valence Bond theory and hybridization concepts
  • Knowledge of molecular structures, particularly pentagonal bipyramidal and octahedral geometries
  • Basic chemistry knowledge regarding xenon and iodine compounds
NEXT STEPS
  • Study the application of VSEPR theory to predict molecular shapes
  • Explore Valence Bond theory in detail, focusing on hybridization types
  • Research the properties and structures of other xenon and iodine compounds
  • Examine the differences in molecular geometry between compounds with and without lone pairs
USEFUL FOR

Chemistry students, educators, and professionals interested in molecular geometry, hybridization, and the properties of xenon and iodine compounds.

mooncrater
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Homework Statement


I am confused about the structure of ##XeF_6##.

Homework Equations

The Attempt at a Solution


Is it octahedral or a pyramid with a pentagonal base? ##Xe## has ##sp^3d^3## hybridization. Then I think the latter one is correct. Since the first one has nonarrangement for the lone pair over ##Xe##.
 
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mooncrater said:

Homework Statement


I am confused about the structure of ##IF_6##.

Homework Equations

The Attempt at a Solution


Is it octahedral or a pyramid with a pentagonal base? ##I ## has ##sp^3d^3## hybridization. Then I think the latter one is correct. Since the first one has nonarrangement for the lone pair over ##I ##.
I think there is no thing as IF6.
It should be [IF6]+ as that is the stable specie.
So it has then a octahedral structure.
 
Raghav Gupta said:
I think there is no thing as IF6.
It should be [IF6]+ as that is the stable specie.
So it has then a octahedral structure.
Sorry I meant to say ##XeF_6##... did that in hurry.
 
mooncrater said:
Sorry I meant to say ##XeF_6##... did that in hurry.
Hey how you edited the title?
Did you reported it to staff?
XeF6 does not have perfect octahedral or the other structure you have showed in attempt.
 
Raghav Gupta said:
Hey how you edited the title?
Did you reported it to staff?
XeF6 does not have perfect octahedral or the other structure you have showed in attempt.
I used the thread tools.
It has ##sp^3d^3## hybridization for sure. But it's structure is still not clear to me.
 
But when we search about ##sp^3d^3## in images section of Google then we can see the structure of ##IF_7## which has ##sp^3d^3## structure. Why it has a different structure?
 
mooncrater said:
But when we search about ##sp^3d^3## in images section of Google then we can see the structure of ##IF_7## which has ##sp^3d^3## structure. Why it has a different structure?
They are saying that it has an unusual pentagonal bi pyramidal structure .
And remember one has lone pair and IF7 does not have that. So some differences will be there.
 
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Ok then... I assume my doubt cleared.
Thank you. (##R\longrightarrow R ## help)
 
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Raghav Gupta said:
They are saying that it has an unusual pentagonal bi pyramidal structure .
And remember one has lone pair and IF7 does not have that. So some differences will be there.
Good call RG... The Pentagonal Bipyramid is correct. Now, can you apply the VSEPR theory and show => AX6E geometry for :XeF6? and then the Valence Bond theory to show how the ground state electron configuration of Xe hybridizes at the valence level to give seven (7) sp3d3 hybrid orbitals? I'll bet you already know how to do it. Go for it!
 

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