Unravelling Hodge Duality: A Starter Guide

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I'm having problems understanding Hodge duality in its most basic form. It relates exterior p forms to exterior n-p forms where n is the dimensionality of the manifold. I can't seem to follow the discussion on the hodge dual operator on this lecture course (page 19):

http://www.damtp.cam.ac.uk/user/gr/about/members/dgnotes3.pdf

How does the star operator bring about all the Faraday 2-form example?

Any help would be appreciated.
Thanks.
 
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the * is "perpendicular" to the original

Gianni2k said:
I'm having problems understanding Hodge duality in its most basic form. It relates exterior p forms to exterior n-p forms where n is the dimensionality of the manifold.

How does the star operator bring about all the Faraday 2-form example?

Hi Gianni2k! :smile:

The defining property is that inner product with the * (an ordinary scalar) is ± the same as outer product with the original:

For example, in Minkowski (+,-,-,-) space, the outer product x^y^z^t = 1, so (*x,y^z^t) = ±1, so *x must be ±y^z^t.

(by comparison, x^x^z^t = 0, so (*x,x^z^t) = (y^z^t,x^z^t) = 0)

and similarly outer product x^y^z^t = 1, so (*(x^y),z^t) = ±1, so *(x^y) must be ±z^t.

It's always the "perpendicular" component:

If we think of a p-form as spanning a p-dimensional subspace (yes, I know we shouldn't!), then its * spans the perpendicular, or complementary, subspace.

*x "is" the three dimensions perpendicular to x, and must therefore be ±y^z^t (± according to the metric).

and *(x^y) must be ±z^t.

So in Faraday, Ex is the x^t component, and so its * is ± the y^z component, which is Bx.

It's this equality between inner product with * and outer product with the original that forces the * to "be" the perpendicular element.

Does that help? :smile:
 
ok great, so why is the outer product on minkowski x^y^z^t=1? And is (x,x) always =1 ?

Also, so in this formalism is the magnetic field the Hodge dual to the electric field in Minkowski space?

thanks.
 
Hi Gianni2k! :smile:
Gianni2k said:
ok great, so why is the outer product on minkowski x^y^z^t=1? And is (x,x) always =1 ?

With the usual (+.-.-.-) metric, (t,t) = 1 and (x,x) = -1.

And the product of all four of x y z and t is ±1, depending on the order they're in (maybe it's x^y^z^t=-1, I haven't checked :redface:)
Also, so in this formalism is the magnetic field the Hodge dual to the electric field in Minkowski space?

Yes (times -1):

*E = -B, *B = E, **E = -E, **B = - B. :smile:
 
In three dimensions forms can be visualized like this:
  • A 1-form is a set of equally spaced planes.
  • A 2-form is a set of equally spaced lines.
  • A 3-form is a set of equally spaced points.
The Hodge dual of a 2-form is then a set of planes perpendicular to the 2-form lines. The spacing between the planes is such that the intersection points between the planes and lines are a lattice with one point per unit volume.

In four dimensions it gets slightly more complicated:
  • A 1-form is a set of equally spaced 3-dimensional linear spaces.
  • A 2-form is one or two sets of equally spaced planes.
  • A 3-form is a set of equally spaced lines.
  • A 4-form is a set of equally spaced points.
The Hodge dual of a simple (i.e. it is only one set of planes) 2-form is another set of planes, perpendicular to the first set and spaced such that the intersection points are a lattice with one point per unit 4-volume.

(Ah, and yes, all lines, planes, etc should have an orientation as well...)

Demystifier said:
By the way, these lectures are referred to as Part III. Do you also have links to other parts?
Part II is found a http://www.damtp.cam.ac.uk/user/gr/about/members/gwglectures.html"
 
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Demystifier said:
By the way, these lectures are referred to as Part III. Do you also have links to other parts?
Part III is the other name for Cambridge's "http://www.maths.cam.ac.uk/postgrad/casm/": their masters course. Thus, these notes are not the third part of a lecture series, but is a complete course taught during the CASM (or Part III).