Upper/Lower Bounds Homework: Solving (a), (b), (c)

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Homework Help Overview

The problem involves a partially ordered set (poset) defined by a relation of divisibility among the elements of the set S = {2,3,4,6,7,8,14,28,42,98}. The tasks include identifying a subset with no upper or lower bounds, finding the least upper bound for a specific pair of elements, and determining if a subset is totally ordered.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the subset {7,3,8} as a candidate for having no upper or lower bounds, questioning the validity of this claim.
  • There is debate over the least upper bound for the set {3,7}, with some participants suggesting that 7 cannot be the least upper bound due to the nature of the divisibility relation.
  • Participants explore the definition of total ordering and provide reasoning regarding the subset {2,6,8}, with some affirming that it is not totally ordered based on divisibility.

Discussion Status

The discussion is active, with participants providing feedback on each other's reasoning. Some guidance has been offered regarding the least upper bound and total ordering, but there remains uncertainty and differing opinions on the correctness of specific answers.

Contextual Notes

Participants are navigating the definitions and properties of posets, particularly focusing on the implications of divisibility and the criteria for upper bounds and total ordering. There is mention of confusion regarding the terminology of maximal and minimal elements in the context of the set S.

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Homework Statement



Let S=P{2,3,4,6,7,8,14,28,42,98} and let p be the relation on S defined by a p b iff a|b. Then (S,p) is a poset.

(a) Find a subset of S which has no upper bound and no lower bound.
(b) Find the least upper bound for {3,7}
(c) Determine wether or not the subset {2,6,8} of S is totally ordered. Justify your answer.

Homework Equations



The Attempt at a Solution



(a) So, I drew a lattice diagram:

http://img514.imageshack.us/img514/8835/72872757.gif

I think the set S'={7,3,8} qualifies as a subset of S which has no upper bound and no lower bound. Am I right?

(b) lub{3,7} = 7 ?

(c) I'm not sure how to answer this question. I think that a "total ordering" on a set means a partial order ~ on a set with the additional property that for any [tex]a,b \in S[/tex] we have a~b or b~a. Here in the subset {2,6,8} of S, 6 is devisible by 2, 6|2, also 8|2 but 6 isn't devisible by 8 or vice versa, so the set isn't totally ordered. Is this correct?
 
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Hi roam! :smile:
roam said:
Let S=P{2,3,4,6,7,8,14,28,42,98} and let p be the relation on S defined by a p b iff a|b. Then (S,p) is a poset.

(a) Find a subset of S which has no upper bound and no lower bound.
(b) Find the least upper bound for {3,7}
(c) Determine wether or not the subset {2,6,8} of S is totally ordered. Justify your answer.

(a) … I think the set S'={7,3,8} qualifies as a subset of S which has no upper bound and no lower bound. Am I right?

(b) lub{3,7} = 7 ?

(c) I'm not sure how to answer this question. I think that a "total ordering" on a set means a partial order ~ on a set with the additional property that for any [tex]a,b \in S[/tex] we have a~b or b~a. Here in the subset {2,6,8} of S, 6 is devisible by 2, 6|2, also 8|2 but 6 isn't devisible by 8 or vice versa, so the set isn't totally ordered. Is this correct?

(a) yes :smile:
(b) nooo :redface:
(c) yes :smile:
 
tiny-tim said:
Hi roam! :smile:


(a) yes :smile:
(b) nooo :redface:
(c) yes :smile:


Hi Tiny tim!

I don't understand why my answer to part (b) is not correct, could you explain please? 3x7=21 which is not even in the bigger set, and the only (and hence smallest) upperbound is 7. :rolleyes:

Also for part (c), is my explanation correct/sufficient (because the question says you must justify the answer)?
 
How can 7 be the least upper bound if 3 isn't less than 7? You say 21 isn't in S, and that's fine... what numbers in S could be the least upper bound?
 
Hi roam! :wink:
roam said:
I don't understand why my answer to part (b) is not correct, could you explain please? 3x7=21 which is not even in the bigger set, and the only (and hence smallest) upperbound is 7. :rolleyes:

Office_Shredder :smile: is right … 3 does not divide 7 (ie, is not "less than" in the ordering), so how can 7 be the lub?
Also for part (c), is my explanation correct/sufficient (because the question says you must justify the answer)?

Yes … you've specifically said that "6 isn't divisible by 8 or vice versa", which itself shows that there is no total ordering … that's fine! :smile:
 
The set has no upper/lower bound since there is no order on the set, 3 & 7 aren't devisible. So is it just the empty set i.e. lub{3,7}= {[tex]\emptyset[/tex]}? :redface:

Tiny tim, there's another question that I'm confused about: "Find all maximal and minimal elements of S."
It says "elements", plural. But there's only one max and one min:
maxP{2,3,4,6,7,8,14,28,42,98}=98
minP{2,3,4,6,7,8,14,28,42,98}=2
 
Hi roam! :smile:

(oh, and it's "divisible"! :wink:)
roam said:
The set has no upper/lower bound since there is no order on the set, 3 & 7 aren't devisible. So is it just the empty set i.e. lub{3,7}= {[tex]\emptyset[/tex]}? :redface:

Forget division … just look at that very good picture you drew … go up from 3 and 7, and where do you get? :smile:

(btw, lub has to be an element

if there's no lub, you just say so, you don't say it's the empty set. :wink:)
Tiny tim, there's another question that I'm confused about: "Find all maximal and minimal elements of S."
It says "elements", plural. But there's only one max and one min:
maxP{2,3,4,6,7,8,14,28,42,98}=98
minP{2,3,4,6,7,8,14,28,42,98}=2

I haven't come across this terminology before :redface:, but I assume maximal means any element that doesn't have anything "higher" …

again, you can just read this off the picture. :smile:
 
Thanks a lot Tiny tim, I get it! :wink:

Forget division … just look at that very good picture you drew … go up from 3 and 7, and where do you get?

lub=42
 
:biggrin: Woohoo! :biggrin:
 

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