Upper & Lower Sums for f(x)=4-x2 on [-1,1]

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SUMMARY

The upper and lower sums for the function f(x) = 4 - x² on the interval [-1, 1] with respect to the partition P{-1, -0.5, 0.5, 1} can be calculated using the definitions of upper and lower sums. The lower sum represents the area under the curve, while the upper sum captures the maximum function values over each subinterval. To compute these sums, one must evaluate the function at the partition points and apply the appropriate formulas for upper and lower sums.

PREREQUISITES
  • Understanding of Riemann sums
  • Familiarity with the function f(x) = 4 - x²
  • Knowledge of partitioning intervals
  • Ability to calculate areas under curves
NEXT STEPS
  • Review the definitions of upper and lower sums in calculus
  • Practice calculating Riemann sums for different functions
  • Explore integration techniques for finding areas under curves
  • Investigate the implications of partitions on sum accuracy
USEFUL FOR

Students studying calculus, particularly those focusing on Riemann sums and integration techniques, will benefit from this discussion.

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Homework Statement



Give the upper sum for f(x)=4-x2 on the interval [-1,1] with respect to the partition P{ -1, -0.5, 0.5, 1]

Give the lower sum for f(x)=4-x2 on the interval [-1,1] with respect to the partition P{ -1, -0.5, 0.5, 1]

Homework Equations


The Attempt at a Solution



How do I do this again? Lower sum should be the area under the curve. You'd just integrate then on the interval given (-1,1) ? Also don't know anymore how to do upper sum.
 
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XodoX said:

Homework Statement



Give the upper sum for f(x)=4-x2 on the interval [-1,1] with respect to the partition P{ -1, -0.5, 0.5, 1]

Give the lower sum for f(x)=4-x2 on the interval [-1,1] with respect to the partition P{ -1, -0.5, 0.5, 1]


Homework Equations



You might try writing the definition of upper and lower sum with respect to a partition here.

The Attempt at a Solution



How do I do this again? Lower sum should be the area under the curve.
No, it would not.
You'd just integrate then on the interval given (-1,1) ?

No.

Also don't know anymore how to do upper sum.

Apparently not. Start by writing the definitions. They will be in your text.
 

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