Urgent: Interfering Waves Homework: Find Speed in Regions A & B

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SUMMARY

The discussion focuses on calculating the speed of water waves in two regions of a ripple tank, using a plane wave generator with a frequency of 60.0 Hz and a wavelength of 3.0 cm. The speed in region A is determined to be 3.14 m/s, while the speed in region B is calculated as 1.03 m/s. Snell's Law is applied to relate the speeds in both regions based on the angles of the wave crests, which are 25.0 degrees in region A and 14.0 degrees in region B. The calculations confirm the velocities derived from the wave properties.

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Homework Statement


A plane wave generator with a freqenecy of 60.0Hz creates a water wave of wavelength 3.0cm in region A of a ripple tank. The angle between the wave crests and straight boundary between regions A and B is 25.0 degrees in region A and 14.0 degrees in region B. Find the speed of the wave in each region.

f = 60.0Hz
lambda = 0.030 m
thedaA = 25.0 degrees
thedaB = 14.0 degrees
vA = ?
vB = ?

Homework Equations



I was thinking to use snell's law, but I am not sure how to...

The Attempt at a Solution



General v...


v = f x lamda
v = 60 x 0.030
v = 1.8 m/s

Find vA


vA/1.8 = Sin25/Sin14
vA = 3.14 m/s

Find vB

vB/1.8 = Sin14/Sin25
vB = 1.03 m/s
 
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kevykevy said:

v = f x lamda
v = 60 x 0.030
v = 1.8 m/s


Yes, so this is already the velocity in region A.

vB/1.8 = Sin14/Sin25
vB = 1.03 m/s

This looks ok at first sight.
 

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