Use energy conservation to determine the forces

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Homework Statement



Consider an isolated system comprising two particles of masses m1 and m2, whose position vectors, in an inertial frame, are x1 and x2 and whose velocity vectors are v1 and v2. The interaction of the particles may be described by an energy function

E = 1/2 m1v1^2 + 1/2 m2v2 ^2 + U(x1, x2).

(a) Suppose that U = −k/r2, where k is a positive constant. Use energy conservation to determine the forces acting between the particles.


Homework Equations



E = 1/2 m1v1^2 + 1/2 m2v2 ^2 + U(x1, x2). (1)

U = −k/r2, (2)

The Attempt at a Solution



substituting U = −k/r2 into (1) gives

E = 1/2 m1v1^2 + 1/2 m2v2 ^2 −k/r2

then don't know what to do to determine the forces ,
i would think that gravtional forces are acting between the particles.
 
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What does r2 mean? r usually denotes distance from x1 to x2. So r2=r^2 or just r? In either case, the force is related to the derivative of the potential energy function U with respect to distance. Why is this post titled 'relativity'?
 
r2 means rsquared which should be r^2
relativity, momentum forces...
well the question was longer , and other parts involved relativty, if u want me to post the rest of the question let me know.
 
(i)Which aspect of Newtonian relativity requires
U to depend only on the separation vector x1 − x2?

(ii) Which further aspect of Newtonian relativity requires U to depend only on the magnitude r = |x1 − x2| of the separation vector?

and part (iii) is given as question (a)
 
Ahhhh! NEWTONIAN relativity. Did you figure out (i) and (ii)? For (iii) I'll reiterate, the force is the negative derivative of the potential. What is the direction of the force?
 
no couldn't do (i) and (ii).

force will act towards the particles
 
Newtonian relativity-The special principle of relativity states that physical laws should be the same in all inertial reference frames, but that they may vary across non-inertial ones
 
So in particular you should be able to translate and rotate positions without affecting the physics (such as forces or potentials). What does this tell you about (i) and (ii)?
 
Last edited:
U= -Gm1m2/ x1-x2

(i)Which aspect of Newtonian relativity requires
U to depend only on the separation vector x1 − x2?

mechanics.
 
yes it is important..well is it gravtional (netwonain relatiity that is reuqired)
 
(i)the principle of conservation of energy
 
(ii) Which further aspect of Newtonian relativity requires U to depend only on the magnitude r = |x1 − x2| of the separation vector?


rotational invariance-

a vector quantity is rotationally invariant if its value remains the same under a rotation of its input vectors. Both the dot product and the cross product are rotationally invariant, while vector addition and scalar multiplication, in general, are not.
 
Basically, yes. x1-x2 is not rotationally invariant but |x1-x2| is. Now, what about your force. The latest version of the potential you sent looks more like -k/r than -k/r^2. Which is it and which force law does that lead to?
 
U = −k/r^2 this is the potenetial that is given in the question.

Newtons force law of gravition:

F= Gm1m2/ r^2
 
gravtional potentional
 
i think-

the force between the objects will be gravitonal potential.
 
Potential is not a force. It's a potential. Gravitational potential has the form -k/r. Your potential has the form -k/r^2, you say. Hence your potential is different and is not gravity. QED. What would the force law coming from your potential be?
 
well FORCE= mass* accelration,

acceleration being gravtional

what doee QED mean?.

What would the force law coming from your potential be?

F= KM1M2/ |x1 − x2|
 
QED just means 'thus it is proved'. You are giving me random answers for what the force is. You said you were given that the potential is -k/r^2. Now forget everything else except that. There is a general relationship between potential and force. What is it?
 
FOrce= qd

where q is the potential and d is the distance
 
f = m g,

U = m g y

Fx = dU / dx,

Fy = dU / dy

w = m g,

E = K + U
 
- dU/ dx= F (x)

U (x) = - integral between x0 to x : F (x) dx + U (xo)