Use partial fractions to integrate x^3/x^3+1

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SUMMARY

The integration of the function x^3/(x^3+1) can be effectively approached using partial fractions after performing long division. The integrand can be rewritten as 1 - 1/(x^3 + 1), allowing for the application of partial fraction decomposition. The final result includes two logarithmic terms and an arctangent term, demonstrating the complexity of the integration process. This method provides a clear pathway to solving the integral without excessive complication.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with long division of polynomials
  • Knowledge of partial fraction decomposition
  • Basic proficiency in logarithmic and arctangent functions
NEXT STEPS
  • Study the process of polynomial long division in detail
  • Learn about partial fraction decomposition techniques
  • Explore integration techniques involving logarithmic and arctangent functions
  • Practice integrating rational functions using similar methods
USEFUL FOR

Students and educators in calculus, mathematicians focusing on integration techniques, and anyone looking to enhance their skills in solving complex integrals using partial fractions.

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Use partial fractions to integrate x^3/(x^3+1)

The Attempt at a Solution



[tex]\int x^{3}/(x^{3}+1) dx[/tex]

Homework Statement


Homework Equations


The Attempt at a Solution



[tex]\int x^{3}/x^{3}+1 dx[/tex]

I know that first i have to perform long division but i am at a loss how to do this

THanks
 
Last edited:
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You can do long division, or you can just rewrite the integrand:

[tex]\frac{x^3}{x^3 + 1} = 1 - \frac{1}{x^3 + 1}[/tex]

Now use partial fractions on that. Something similar comes out of long division. Then you have a big mess to slog through. The answer has two log terms and an arctan term.
 
If you are wondering how hgfalling got that without doing "long division", I suspect the rewrote it as
[tex]\frac{x^3}{x^3+ 1}= \frac{x^3+ 1- 1}{x^3+ 1}= \frac{x^3+ 1}{x^3+ 1}- \frac{1}{x+1}[/tex]
 

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