The discussion focuses on using spherical coordinates to compute the area of a disk centered at (0, 0, 4) with a radius of 3. The original attempt involved a triple integral, specifically ∫∫∫ (r^2 * sin(θ)) with limits from φ = 0 to 2π, θ = 0 to arcsin(3/5), and r = 5sin(θ) to 5. Participants clarified that a single or double integral is sufficient for area calculation and emphasized the necessity of including differentials in the integral setup.
PREREQUISITESStudents in calculus courses, educators teaching multivariable calculus, and anyone looking to improve their understanding of integration techniques in spherical coordinates.
This is way off. To compute area you need only a single integral or at most a double integral.kougou said:Homework Statement
Use spherical cords to compute area of a disk, that's center at x,y=0, and z=4, having a radius of 3
Homework Equations
I set up a triple ∫∫∫ (r^2* sin(theta)), running from phi =0 to 2pi,
theta=0 to arcsin(3/5), r=5sin(theta) to 5.
kougou said:The Attempt at a Solution
It doesn't give me a current answer. What's wrong
Am I even on the right track?