Using Differentials to approximate error

Click For Summary
In the discussion, the distinction between ΔV and dV is clarified, with ΔV representing the actual error and dV serving as the approximate error. The conversation emphasizes that while ΔV is the true error in a measurement, dV is derived from linear approximation techniques. It is noted that in practical scenarios, measurements come with explicit bounds, and the goal is to calculate the maximum error in derived values, such as volume. The term "error" is deemed potentially misleading, suggesting that "uncertainty" might be a more accurate descriptor. Understanding these concepts is crucial for accurately estimating measurement uncertainties in mathematical applications.
theBEAST
Messages
361
Reaction score
0

Homework Statement


Here is the problem with the solution:http://dl.dropbox.com/u/64325990/MATH%20253/Capture.PNG

I don't understand how dV is the error. Isn't the error the actual value - the estimated value? In other words, ΔV-dV?
 
Last edited by a moderator:
Physics news on Phys.org
theBEAST said:

Homework Statement


Here is the problem with the solution:http://dl.dropbox.com/u/64325990/MATH%20253/Capture.PNG

I don't understand how dV is the error. Isn't the error the actual value - the estimated value?
Yes.
In other words, ΔV-dV?
No. \Delta V and "dV" are not the "actual value" and "estimated value" of the function. \Delta V is the actual error itself and the differential, "dV", is the approximate error as your title to this thread indicates.
 
Last edited by a moderator:
Often times you will have an error in a particular measurement, call it sigmax, but you want to know the error in a function of the measurement, sigmaf. To approximate how this error "propagates" through, one can treat the error terms as differentials and solve, using linear approximation (ie throwing away all of the higher order terms), for df treating sigmax as approximately equal to dx. Remember that this is not exactly true, and it is only true as an approximation.

In your problem, the value of the measurement was given with explicit bounds. Thus, the problem wants you to calculate the maximum error in the calculated volume. In real life, results are usually given to plus or minus some multiple of a standard deviation about a mean value, and we can never be completely sure that the true result lies within the interval we measured.

It is unfortunate that it is called "error" because the word "error" can be a bit confusing since there are many different ways of reporting the concept of error. Perhaps a better word for what you are doing is estimating the "uncertainty"?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
29K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K