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Using division of power series to find the first 3 nonzero terms

  1. Jul 30, 2008 #1
    1. Use multiplication or division of power series to find the first 3 nonzero terms in the Maclaurin series of the function x/sinx.



    2. the maclaurin series for sinx is [tex]\sum(-1)^{n}x^{2n+1}/(2n+1)![/tex]



    3. I've tried to divide x/sinx substituting sinx for the maclaurin series but I seem to get stuck. Any help is much appreciated!
     
  2. jcsd
  3. Jul 30, 2008 #2

    Dick

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    You are probably making too much of a big deal over this.
    sin(x)=x-x^3/6+x^5/120-... Just do polynomial long division of that into x. You can just keep the first three terms. Stop after you get three terms in the quotient.
     
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