Using division of power series to find the first 3 nonzero terms

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SUMMARY

The discussion focuses on using polynomial long division of power series to derive the first three nonzero terms of the Maclaurin series for the function x/sin(x). The Maclaurin series for sin(x) is given by the formula ∑(-1)^{n}x^{2n+1}/(2n+1)!. Participants suggest substituting this series into the division process and emphasize the importance of stopping after obtaining three terms in the quotient. This method effectively simplifies the calculation and provides the desired terms without unnecessary complexity.

PREREQUISITES
  • Understanding of Maclaurin series expansion
  • Familiarity with polynomial long division
  • Knowledge of basic calculus concepts
  • Ability to manipulate power series
NEXT STEPS
  • Practice polynomial long division with various power series
  • Explore the derivation of Maclaurin series for other functions
  • Learn about convergence of power series
  • Investigate applications of power series in solving differential equations
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Students and educators in mathematics, particularly those studying calculus and series expansions, as well as anyone interested in advanced techniques for series manipulation.

gummybears123
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1. Use multiplication or division of power series to find the first 3 nonzero terms in the Maclaurin series of the function x/sinx.



2. the maclaurin series for sinx is [tex]\sum(-1)^{n}x^{2n+1}/(2n+1)![/tex]



3. I've tried to divide x/sinx substituting sinx for the maclaurin series but I seem to get stuck. Any help is much appreciated!
 
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You are probably making too much of a big deal over this.
sin(x)=x-x^3/6+x^5/120-... Just do polynomial long division of that into x. You can just keep the first three terms. Stop after you get three terms in the quotient.
 

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