Using Effective Potential to Describe motion of an object

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The discussion focuses on using effective potential to describe the motion of an object attached to a rotating rod system. The effective potential graph illustrates the object's motion, starting from a low point, moving downward to a lowest point, then upward parabolically, and repeating the cycle. Key terms include gravitational potential energy, angular velocity (omega), and the length of the arm (L). The participants seek clarification on the definitions of energy (E) and effective potential (Veff), as well as the role of mass (m) and length (L) in the equations. Understanding these concepts is crucial for accurately analyzing the system's dynamics.
Junkwisch
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Hey guy, this is one of the question in my uni work (I'm not sure whether my answer is correct or not, please have a check). The attachment consists of what the effective potential graph look like.





"It starts from a low point where it move downward to the lowest point. It then move upward to the highest point then to the lowest point parabolically. It then move upward to the low point (where the motion start) and restart the entire process again."



I treat the effective potential as the displacement of the object in Y, since the only potential energy acting in here is gravitational. Omega represent angular velocity, g= acceleration due to gravity and L represents the length if the arm.


Best Regards
Naphat Veraphong
 

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  • 10320450_545476042236845_8139763089570184449_n.jpg
    10320450_545476042236845_8139763089570184449_n.jpg
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Can you define all the terms you are using?
 
Two light, inextensible rods OP and PQ are joined at P by means of a frictionless hinge. The
rod OP stands vertically. Its base O is glued to the centre of a rotating turntable. The rod PQ
makes an angle θ(t) with respect to the vertical, which changes as a function of time t, with
0 ≤θ(t) ≤ pi . Both rods rotate around the axis OP with constant angular velocity Ω. A point
mass m is attached to the free end Q of the rod PQ.

L is the length of rod PQ, g is uniform acceleration due to gravity
 
What is E and Veff?
 
E is the energy while Veff is effective potential
 
Not sure why the mass m and length L terms are missing from the equation for E.

What is the definition of the effective potential?
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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