- #1

NoahCygnus

- 96

- 2

*"Let us derive an expression for the potential energy associated with an object at a given location above the surface of earth. Consider an external agent lifting an object of mass ##m## from an initial height ##y_{i}##above the ground to a final height ##y_{f}##. We assume the lifting is done slowly with no acceleration so the applied force from the agent can be modeled as being equal to in magnitude to the gravitational force on the object. The work done by the external agent on the earth-object system as the object undergoes this upward displacement is given by : ##W_{net} = \vec{Fapp}\cdot \Delta \vec{r} = mg\hat{j}\cdot[(y_{f} - y_{i})\hat{j}] = mgy_{f} - mgy_{i}##*

Where this result is the

Therefore ##W_{net} = \Delta U_{g}##."

Where this result is the

**net work done**on the system because the applied force is only force by the environment. The equation represents a transfer of energy into the system and the energy appears in a different form called potential energy. Therefore we call the quantity ##mgy## as the gravitational potential energy ##U_{g}##. ##U_{g} \equiv mgy##.Therefore ##W_{net} = \Delta U_{g}##."

What I don't understand is , why has the author stated that only the external force does

**on the system? Why didn't the author include the work done due to gravity in the net work? Shouldn't the net work done on the system be ##W_{net} = W_{app} + W_{g}## , which is the sum of all the works done by both external and internal forces?**

*net work done*