- #1

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## Homework Statement

Use KCL and KVL to determine the currents I1 to I3 in the circuit below:

## Homework Equations

Ʃ[itex]v_{n}[/itex] = 0

Ʃ[itex]i_{n}[/itex] = 0

v=ir

## The Attempt at a Solution

I got two different answers for [itex]I_{1}[/itex] using the two different laws. I'm not sure if I'm doing it right.

KVL @ loop 1: -18 + 6 + 8[itex]I_{1}[/itex] = 0

8 [itex]I_{1}[/itex] = 12

[itex]I_{1}[/itex] = 1.5A

KCL @ node a: 3 = [itex]I_{1}[/itex] + [itex]I_{2}[/itex] + 1

KCL @ node b: [itex]I_{3}[/itex] = 1 + [itex]I_{2}[/itex]

0 = [itex]I_{1}[/itex] + [itex]I_{2}[/itex] -2

0 = -1 - [itex]I_{2}[/itex] + [itex]I_{3}[/itex]

1 = [itex]I_{3}[/itex]

0 = [itex]I_{2}[/itex]

2 = [itex]I_{1}[/itex]