Using substiution of the form v=1/y^k to solve 1st order DE

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xy'+3y+4y^3=0
use substitution of the form v=1/y^k for some positive integer k. Choose a value of k that cancels the y^3 term.
 
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useruseruser said:
xy'+3y+4y^3=0
use substitution of the form v=1/y^k for some positive integer k. Choose a value of k that cancels the y^3 term.
Well, have you tried at all? There's not a whole lot of deep thinking involved! Just do exactly what they tell you to do. If v= 1/y^k[/itex], then y= 1/v^{1/k}. Find the derivative of y and plug it and y into the equation. There should be a single value of k that simplifies the equation.
 
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