Using the conservation of energy find speed

AI Thread Summary
The discussion revolves around calculating the speed of a mass released from a compressed spring using the conservation of energy principle. Initially, the kinetic energy equations were set up without considering gravitational potential energy, leading to confusion. Participants clarified that both spring potential energy and gravitational potential energy must be included in the calculations. After incorporating these factors, the corrected speed of the mass was determined to be approximately 2.38 m/s. The conversation also included a personal exchange between participants, indicating a connection outside the academic context.
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Homework Statement


A spring, having a force constant of 6.0x102 N/m, is held in a vertical position and compressed 0.30m. A 5.0 kg mass is then placed on top of the spring. THe mass is then releases. Neglecting air resistance and the mass of the spring

The Attempt at a Solution



Ek1 = Ek2
1/2kx^2 = 1/2kx^2 + 1/2mv^2
1/2(600N/m)(0.3m)^2 = 1/2(600N/m)(0.2m)^2 + 1/2(5 kg)v^2
27 J - 12 J = (2.5 kg)v^2
2.45 m/s=V

Im confused if we need to add any sort of gravitational potential energy to the ball?
 
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Lolagoeslala said:

Homework Statement


A spring, having a force constant of 6.0x102 N/m, is held in a vertical position and compressed 0.30m. A 5.0 kg mass is then placed on top of the spring. THe mass is then releases. Neglecting air resistance and the mass of the spring

The Attempt at a Solution



Ek1 = Ek2
1/2kx^2 = 1/2kx^2 + 1/2mv^2
1/2(600N/m)(0.3m)^2 = 1/2(600N/m)(0.2m)^2 + 1/2(5 kg)v^2
27 J - 12 J = (2.5 kg)v^2
2.45 m/s=V

Im confused if we need to add any sort of gravitational potential energy to the ball?
You need to consider both gravitational and spring potential energies and kinetic energy. Are you trying to determine the speed when the mass leaves the spring?
 
PhanthomJay said:
You need to consider both gravitational and spring potential energies and kinetic energy. Are you trying to determine the speed when the mass leaves the spring?

yes, the velocity when it has moved up 0.20 m from the compressed position on the spring.
 
When it moves up 0.2 m, the spring is now compressed by how much? Don't forget the gravitational PE.
 
PhanthomJay said:
When it moves up 0.2 m, the spring is now compressed by how much? Don't forget the gravitational PE.

umm... 0.1?
 
PhanthomJay said:
Yes.

so
Ek1 = Ek2
1/2kx^2 = 1/2kx^2 + 1/2mv^2
1/2(600N/m)(0.3m)^2 = 1/2(600N/m)(0.1m)^2 + 1/2(5 kg)v^2
27 J - 3 J = (2.5 kg)v^2
3.098 m/s=V
 
What happened to the gravitational potential energy term you were inquiring about??
 
PhanthomJay said:
What happened to the gravitational potential energy term you were inquiring about??

umm what do you mean?
 
  • #10
PhanthomJay said:
What happened to the gravitational potential energy term you were inquiring about??

Ek1 = Ek2
1/2kx^2 = 1/2kx^2 + 1/2mv^2
1/2(600N/m)(0.3m)^2 = 1/2(600N/m)(0.2m)^2 + 1/2(5 kg)v^2 + (5 kg)(9.8 m/s^2)(0.2 m)
27 J - 3 J - 9.8 J= (2.5 kg)v^2
2.38 m/s=V
 
  • #12
phanthomjay said:
looks good now!

thanks :d
 
  • #13
Tell me who u are, u go to my school. DONT IGNORE ME
 
  • #14
Tupac said:
Tell me who u are, u go to my school. DONT IGNORE ME

? who r u?
 
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