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Using the definition of the partial derivative

  1. Mar 6, 2009 #1
    I need some help with this partial derivative. I can do it by rules, but when I try and do it out using the definition of the partial derivative, I run into problems.

    1. The problem statement, all variables and given/known data
    Find the partial derivative of sqrt[x]y^2 - 4xy with respect to x


    3. The attempt at a solution
    Going through while holding a variable constant and using basic derivative rules, I was able to get:

    (y^2) / 2sqrt[x] - 4y
     
  2. jcsd
  3. Mar 6, 2009 #2

    lanedance

    User Avatar
    Homework Helper

    hi
    As long as that is
    (y^2) / (2.sqrt[x]) - 4y
    looks good to me...
     
  4. Mar 6, 2009 #3
    I got that answer by using derivative rules, and not by the definition. When you plug in x+h for x you get sqrt[x+h].. and thats where I'm getting stuck.

    I come out getting this:

    (4hy + (sqrt[x+h] - sqrt[x])y^2)/h
     
  5. Mar 6, 2009 #4

    Mark44

    Staff: Mentor

    It's getting close to bedtime, so I don't have time to check your work up to this point. Assuming that it's correct up to this point, split the expression above into the sum of two terms, like so:
    4hy/h + (sqrt(x + h) - sqrt(x))*y
    [tex]\frac{4hy}{h} + \frac{y^2(\sqrt{x + h} - \sqrt{x})}{h}[/tex]

    It'll be easy to take the limit as h goes to zero for the term on the left, but the one on the right needs a trick, namely to multiply it (the quotient on the right) by 1 in the form of
    [tex]\frac{\sqrt{x + h} + \sqrt{x}}{\sqrt{x + h} + \sqrt{x}}[/tex]

    That should give you something that you can take the limit on.
     
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