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## Homework Statement

Find I in the circuit using the superposition principle

## Homework Equations

superposition:

I = i_1 + i_2 + i_3

## The Attempt at a Solution

for i_1 we neglect the 12V and the 4A sources:

(8 + 2 + 6)i_1 - 16 = 0

i_1 = 1A

for i_2 we neglect the 16V and the 4A sources:

(8 + 2 + 6)i_2 + 12 = 0

i_2 = -0.75

i don't actually know how to solve for the current in i_3:

since there are two nodes only i use parallel resistors:

6 + 8 = 14ohms..... and 2 ohms are parallel

1/14 + 1/2 = 1/R

R = 1.75

current source = 4 A

so the current source and 1.75 are in parallel... so what i need is to solve the outer current,i_3

now im really stuck can someone help pls

ans. I = 0.75A

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