Using Triangle Inequality to find a magnitude

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SUMMARY

The discussion focuses on using the Triangle Inequality to estimate the magnitude |x-y| given the conditions |x-a| < E and |y-a| < E. The Triangle Inequality states that |x-y| ≤ |x-a| + |y-a|, which allows for the derivation of an upper bound for |x-y|. By substituting |x-a| and |y-a| with E, the conclusion is that |x-y| < 2E. This establishes a clear relationship between the distances of x and y from a, providing a method to estimate their difference.

PREREQUISITES
  • Understanding of the Triangle Inequality theorem
  • Familiarity with real number properties
  • Basic algebraic manipulation skills
  • Knowledge of epsilon-delta definitions in calculus
NEXT STEPS
  • Study the application of the Triangle Inequality in various mathematical proofs
  • Explore epsilon-delta definitions in calculus for limits
  • Learn about metric spaces and their properties
  • Investigate other inequalities in analysis, such as Cauchy-Schwarz inequality
USEFUL FOR

Students in mathematics, particularly those studying real analysis or calculus, as well as educators looking for methods to explain the Triangle Inequality and its applications in estimating distances.

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Homework Statement


Let a, x, and y be real numbers and let E > 0. Suppose that |x-a|< E and |y-a|< E. Use the Triangle Inequality to find an estimate for the magnitude |x-y|.


Homework Equations


The Triangle Inequality states that |a+b| <= |a| + |b| is valid for all real numbers a and b.


The Attempt at a Solution



|x-a| = |x-y+y-a| <= |x-y| + |y-a|

I'm fairly certain this conversion/inequality is important because it contains three of the four elements from the problem ( |x-a|, |y-a|, and |x-y|). However, I am stuck on how to get E involved and determine an estimate for |x-y|.
 
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you want to try and get |x-y| on the left of the <= sign

now its a little confusing as you used "a" in the tri eq as well (good notation always helps avoid confusion), so let's re-write it
|c+b| <= |c|+ |b|

then how about letting
c=x-a
n=a-y
 

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