Using U-Substitution to Find an Integral

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lch7
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So I was messing around with some basic u-sub calculus and came across this problem. Any help would be greatly appreciated!

Homework Statement



[itex]\int[/itex] [itex]\frac{3x^{2}}{x^{2}-7}[/itex] dx

Homework Equations


I'm using u-substitution, as stated at the beginning.

The Attempt at a Solution


I see that the u could be the denominator and the numerator is the derivative, or du.

[itex]\int[/itex] [itex]\frac{du}{u}[/itex]

[itex]\int[/itex] [itex]\frac{1}{u}[/itex] du

ln|u|+C

ln|x[itex]^{2}[/itex]|+C

I'm pretty sure this is the correct answer, but I decided to integrate it with the boundaries x=1 and x=4.5.

[ln|x[itex]^{2}[/itex]-7|][itex]^{4.5}_{1}[/itex]

ln|13.25| - ln|-6|
ln(13.25) - ln(6)
2.5839-1.7917
.7922

So this is my final answer, but it just doesn't seem right. I graphed the function and saw it was under the x-axis. Is this the problem?
 
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lch7 said:
So I was messing around with some basic u-sub calculus and came across this problem. Any help would be greatly appreciated!

Homework Statement



[itex]\int[/itex] [itex]\frac{3x^{2}}{x^{2}-7}[/itex] dx

Homework Equations


I'm using u-substitution, as stated at the beginning.

The Attempt at a Solution


I see that the u could be the denominator and the numerator is the derivative, or du.

But if ##u=x^2-7## then ##du = 2xdx## and that is not what you have in the numerator. Try one long division step and see what to do next.
 
Oh man I feel like an idiot! Thankyou all!