V of 2 parallel lines makes cylinders

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Homework Help Overview

The problem involves calculating the electric potential V due to infinitely long parallel wires with charge densities, and demonstrating that the equipotential surfaces are circular cylinders. The context is rooted in electrostatics, specifically related to potential and electric fields.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the potential and is uncertain about demonstrating the shape of the equipotential surfaces. They express confusion regarding how to show that these surfaces are circular cylinders.

Discussion Status

Some participants have noted the original poster's reference to the solutions manual, indicating a potential reliance on external resources. There is a lack of consensus on the approach for part B, with some clarification needed on whether it was included in the manual.

Contextual Notes

There is mention of the original question and its relation to the solutions manual, which may influence the discussion. The original poster has indicated that their solution for part A aligns with the manual, suggesting a focus on part B for further exploration.

bowlbase
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Homework Statement


Expanded from Griffith's (3rd ed) #2.47

Infinitely long wires parallel to x-axis carrying ±λ charge densities intersect the y-axis at ±a.

A) Calculate V(x,y,z) if V(0,0,0)=0
B)Show that the equipotential surfaces are circular
cylinders. Locate the axis and calculate the
radius of the cylinder that is at potential V0.

Homework Equations


Gauss, -∫Edl
E=-∇V
?x2+y2=r2?

The Attempt at a Solution



I've found the solution to part A easily enough but I'm not sure how to approach B. I know that at the origin the potential is zero along the x-axis but I'm confused by how I should show that these are both circular cylinders.

I'd post my solution for A but it's exactly the same as the solution manual so it's easy enough to find.

Any help would be appreciated.
 
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I'd post my solution for A but it's exactly the same as the solution manual so it's easy enough to find.

Why not look at your solutions manual. . .
 
The part b is not part of the original question. Thus, not in the manual.
 
hmm, never mind I guess it was in the manual. Sorry thought that he just added it. thanks anyway.
 

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