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It would seem so
If
<br /> \sum\limits_{n = 1}^{\inf } {|{f(n,x)}|}<br /> is uniformly convergent on [a,b], then is <br /> \sum\limits_{n = 1}^{\inf } {{f(n,x)}}<br /> uniformly convergent.
I said yes. And just applied the Weierstrass Test with |f(n,x)| <= |f(n,x)| (a basic comparison test)
Should still be valid right? Since the absolutely value is Uniformly Cauchy
Homework Statement
If
<br /> \sum\limits_{n = 1}^{\inf } {|{f(n,x)}|}<br /> is uniformly convergent on [a,b], then is <br /> \sum\limits_{n = 1}^{\inf } {{f(n,x)}}<br /> uniformly convergent.
Homework Equations
The Attempt at a Solution
I said yes. And just applied the Weierstrass Test with |f(n,x)| <= |f(n,x)| (a basic comparison test)
Should still be valid right? Since the absolutely value is Uniformly Cauchy