Van der Waals Equation and specific heat

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SUMMARY

The discussion focuses on the application of the Van der Waals equation of state, specifically in relation to calculating the change in internal energy (du) and specific entropy (ds) for a gas with constant specific heat (cv). The Van der Waals equation is given as (P + a/v²)(v - b) = RT, where v = V/n. The participants clarify that for non-ideal gases, the change in internal energy also depends on pressure, and the relevant equation for du is dU = CvdT + [T(∂P/∂T)v - P]dV. This equation is applicable to Van der Waals gases, and the substitution of the Van der Waals equation into the derived terms is essential for solving the problem.

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  • Basic principles of non-ideal gas behavior
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Kelsi_Jade
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The problem reads:
Consider a gas with constant specific heat cv and the van der waals equation of state
(P+ a/v2)(v-b)=RT , where v=V/n

A) Find du and the specific internal energy u=U/n
B) Find ds and the specifi entropy s=S/n


Here's what I've tried so far:

A) I took the initial equation and subbed in the v=V/n :
(P+ a/(V/n)2)(V/n-b)=RT

I know that du= cvdT which can be rearranged cv = du/dT so that is where I can find the du is from the specific heat. However, I don't understand how the van der waals equation can be related mathematically to specific heat?
I know that a=a measure of attraction between particles and b=the volume excluded by a mol of particles. Do I need to solve for these first?

Any help is appreciated!
 
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Kelsi_Jade said:
The problem reads:
Consider a gas with constant specific heat cv and the van der waals equation of state
(P+ a/v2)(v-b)=RT , where v=V/n

A) Find du and the specific internal energy u=U/n
B) Find ds and the specifi entropy s=S/n


Here's what I've tried so far:

A) I took the initial equation and subbed in the v=V/n :
(P+ a/(V/n)2)(V/n-b)=RT

I know that du= cvdT which can be rearranged cv = du/dT so that is where I can find the du is from the specific heat. However, I don't understand how the van der waals equation can be related mathematically to specific heat?
I know that a=a measure of attraction between particles and b=the volume excluded by a mol of particles. Do I need to solve for these first?

Any help is appreciated!
dU = cv only for an ideal gas. For a non-ideal gas, u also depends on pressure P. Have you learned the general equation for du in terms of dT and dP?
 
I found this equation:
dU=CvdT+ [T(∂P/∂T)v - P]dV
but it doesn't mention anything about being related to van der waals' equation so I'm not sure if this is relevant?? Honestly, our text doesn't go much into detail on van der waals so I'm pretty lost..
 
Kelsi_Jade said:
I found this equation:
dU=CvdT+ [T(∂P/∂T)v - P]dV
but it doesn't mention anything about being related to van der waals' equation so I'm not sure if this is relevant?? Honestly, our text doesn't go much into detail on van der waals so I'm pretty lost..
Your equation is supposed to apply to any gas (or liquid), so it should be applicable to a vdW gas. Yes, the vdW equation is relevant. So you substitute the vdW equation into the term in parenthesis. Incidentally, the dV should be dv.
 

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