(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Suppose 1 g of water vaporizes isobarically at atmosphere pressure (1.013 x 10^{5}Pa). Its volume in the liquid state is Vi = 1 cm^{3}, and its volume in the vapor state is Vf = 1671 cm^{3}. Find the change in internal energy

2. Relevant equations

[tex]\Delta U = \Delta Q - \Delta W[/tex]

[tex]\Delta W = p*\Delta V[/tex]

3. The attempt at a solution

I want to ask about [tex]\Delta V[/tex].

[tex]\Delta V = V_2-V_1[/tex]

V_{2}= Vf, and what is V_{1}? Is it Vi or is it zero because volume of vapor is zero initially?

Thanks

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# Homework Help: Vaporization and change in internal energy

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